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0.07x^2+0.05x-350=0
a = 0.07; b = 0.05; c = -350;
Δ = b2-4ac
Δ = 0.052-4·0.07·(-350)
Δ = 98.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.05)-\sqrt{98.0025}}{2*0.07}=\frac{-0.05-\sqrt{98.0025}}{0.14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.05)+\sqrt{98.0025}}{2*0.07}=\frac{-0.05+\sqrt{98.0025}}{0.14} $
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